-16x^2+64x+48=0

Solution for -16x^2+64x+48=0 equation:

-16x^2+64x+48=0

a = -16; b = 64; c = +48;
Δ = b2-4ac
Δ = 642-4·(-16)·48
Δ = 7168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7168}=\sqrt{1024*7}=\sqrt{1024}*\sqrt{7}=32\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-32\sqrt{7}}{2*-16}=\frac{-64-32\sqrt{7}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+32\sqrt{7}}{2*-16}=\frac{-64+32\sqrt{7}}{-32}
$